3(y-4)+y^2=y(y+3)-12

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Solution for 3(y-4)+y^2=y(y+3)-12 equation:


Simplifying
3(y + -4) + y2 = y(y + 3) + -12

Reorder the terms:
3(-4 + y) + y2 = y(y + 3) + -12
(-4 * 3 + y * 3) + y2 = y(y + 3) + -12
(-12 + 3y) + y2 = y(y + 3) + -12

Reorder the terms:
-12 + 3y + y2 = y(3 + y) + -12
-12 + 3y + y2 = (3 * y + y * y) + -12
-12 + 3y + y2 = (3y + y2) + -12

Reorder the terms:
-12 + 3y + y2 = -12 + 3y + y2

Add '12' to each side of the equation.
-12 + 3y + 12 + y2 = -12 + 3y + 12 + y2

Reorder the terms:
-12 + 12 + 3y + y2 = -12 + 3y + 12 + y2

Combine like terms: -12 + 12 = 0
0 + 3y + y2 = -12 + 3y + 12 + y2
3y + y2 = -12 + 3y + 12 + y2

Reorder the terms:
3y + y2 = -12 + 12 + 3y + y2

Combine like terms: -12 + 12 = 0
3y + y2 = 0 + 3y + y2
3y + y2 = 3y + y2

Add '-3y' to each side of the equation.
3y + -3y + y2 = 3y + -3y + y2

Combine like terms: 3y + -3y = 0
0 + y2 = 3y + -3y + y2
y2 = 3y + -3y + y2

Combine like terms: 3y + -3y = 0
y2 = 0 + y2
y2 = y2

Add '-1y2' to each side of the equation.
y2 + -1y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
0 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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